0.2x^2-43x+300=0

Solution for 0.2x^2-43x+300=0 equation:

0.2x^2-43x+300=0

a = 0.2; b = -43; c = +300;
Δ = b2-4ac
Δ = -432-4·0.2·300
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{1609}}{2*0.2}=\frac{43-\sqrt{1609}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{1609}}{2*0.2}=\frac{43+\sqrt{1609}}{0.4}
$